50y^2-162=0

Solution for 50y^2-162=0 equation:

50y^2-162=0

a = 50; b = 0; c = -162;
Δ = b2-4ac
Δ = 02-4·50·(-162)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*50}=\frac{-180}{100}
=-1+4/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*50}=\frac{180}{100}
=1+4/5
$